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What is #f(-2)# for the function #f(x) = 1/(x^2+1)#?

Answer 1

Genesis Allen

#f(-2) = 1/5#

#f(-2) = 1/(2^2 + 1) = 1/5#

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Answer 2

Nathan Axel

To find f(-2) for the function f(x) = 1/(x^2+1), substitute -2 for x:

f(-2) = 1/((-2)^2 + 1) = 1/(4 + 1) = 1/5

Therefore, f(-2) = 1/5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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