# What is/are the vertical asymptote(s) for #y=(x^2+2x)/(x^2+5x-6)#?

By signing up, you agree to our Terms of Service and Privacy Policy

To find the vertical asymptote of any function all we need to do is find where this function is undefined. If a function is undefined when its' denominatore equals 0 (dividing by 0) then we can find the vertical asymptote by taking the denominator and setting it equal to 0.

Now we can factor this piece of the function.

We have 2 vertical asymptotes because we have 2 numbers that make the denominator=0

By signing up, you agree to our Terms of Service and Privacy Policy

The vertical asymptotes for the function y=(x^2+2x)/(x^2+5x-6) are x=-6 and x=1.

By signing up, you agree to our Terms of Service and Privacy Policy

- How do you find the limit of #f(x)=(secx-1)/x^2# as x approaches 0?
- How do you evaluate the limit of #x+sinx# as #x->0#?
- For what values of x, if any, does #f(x) = 1/((x-2)(x-1)(e^x-3)) # have vertical asymptotes?
- How do you use the Squeeze Theorem to find #lim (arctan(x) )/ (x)# as x approaches infinity?
- How do you evaluate #(sin^3x+cos^3x )/( cosx + sinx)# as x approaches #3pi/4#?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7