What is an example hardy-weinberg equation practice problem?

Question

Isabella Anderson · Accepted Answer

A query might appear as follows:

In a population where #mathbf98# out of #mathbf200# individuals exhibit the recessive phenotype, what proportion of the population do you think would be heterozygotes?

An overview, guided through:

The genotype and allele relationships in a population meeting specific criteria are represented mathematically by the Hardy-Weinberg equilibrium. These relationships are as follows:

Alleles: #p+q=1#

#p^2+2pq+p^2=1# is the genotype.

Given that #98# of #200# individuals exhibit the recessive phenotype as inferred from the question, these #98# individuals also have the homozygous recessive genotype, with a frequency equal to #q^2#.

Now that we know that #q^2=0.49#, we can divide #98/200=0.49# to find the true frequency.

But since we want to know the frequency of the heterozygous population, which is equal to #2pq#, we need to know both #p# and #q#.

locating #mathbfq#

#q^2=0.49#

Take each side's square root.

#q=0.7#

(This indicates that recessive alleles make up #70%# of the alleles in the system.)

Using the allele equation, we can now determine the value of #p# after determining the value of #q#.

locating #mathbfp#

Enter #q=0.7# into the equation #p+q=1#.

#p+0.7=1#

To determine this, subtract #0.7# from each side.

#q=0.3#

Determining the heterozygotes' frequency:

# "frequency of heterozygous genotypes" =2pq#

For #p# and #q#, substitute the known values:

#"frequency of heterozygous genotypes" = 2(0.3)(0.7) = 0.42#

When we translate this into a percentage, we discover that #42%# of people are heterozygous.

Logan Allen · Answer

undefined Sure, here's an example Hardy-Weinberg equation practice problem:

In a population of 500 individuals, 36% exhibit a recessive trait (aa). Calculate the frequencies of the homozygous dominant (AA) and heterozygous (Aa) genotypes, and verify if the population is in Hardy-Weinberg equilibrium.