What is an equation of the line tangent to the graph of #y=cos(2x)# at #x=pi/4#?
What is an equation of the line tangent to the graph of #y=cos(2x)# at #x=pi/4# ?
What is an equation of the line tangent to the graph of
Now use point slope form to find the equation of the tangent line:
This gives us:
Simplifying,
Hope that helps! graph{(y-cos(2x))(y+2x-pi/2)=0 [-2.5, 2.5, -1.25, 1.25]}
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The equation of the line tangent to the graph of y=cos(2x) at x=pi/4 is y = -sqrt(2)/2(x - pi/4) + sqrt(2)/2.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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