What is an antimarkovnikov halogenation?

Answer 1

An anti-Markovnikov halogenation is the free-radical addition of hydrogen bromide to an alkene.

In the Markovnikov addition of HBr to propene, the H adds to the C atom that already has more H atoms. The product is 2-bromopropane.

In the presence of peroxides, the H adds to the C atom that has fewer H atoms. This is called anti-Markovnikov addition. The product is 1-bromopropane.

The reason for anti-Markovnikov addition is that it is the Br atom that attacks the alkene. It attacks the C atom with the most H atoms, so the H adds to the C atom with the fewest H atoms.

Here is a video on the anti-Markovnikov addition of HBr to alkenes.

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Answer 2

Antimarkovnikov halogenation is a chemical reaction where a hydrogen atom and a halogen atom (e.g., bromine or chlorine) add to an unsaturated compound, such as an alkene or alkyne, in a way that the halogen attaches to the carbon with fewer hydrogen substituents. This is in contrast to the traditional Markovnikov addition, where the halogen adds to the carbon with more hydrogen substituents.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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