# What is a general solution to the differential equation #y^2=y^2y'=6-x^3#?

That question has 2 equalities that make no sense. Is there a typo?

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To find the general solution to the differential equation ( y^2 = y^2 y' = 6 - x^3 ), you can follow these steps:

- Rewrite the equation to isolate ( y' ): ( y^2 y' = y^2 - 6 + x^3 ).
- Divide both sides by ( y^2 ): ( y' = \frac{{y^2 - 6 + x^3}}{{y^2}} ).
- Rewrite ( y' ) as ( \frac{{dy}}{{dx}} ).
- Rewrite the equation in terms of ( \frac{{dy}}{{dx}} ) and ( y ).
- Solve the resulting separable differential equation.
- Integrate both sides to find the general solution.

The final general solution will be expressed in terms of ( x ) and ( y ).

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