What is #[(8+5)(6-2) ^2] - (417 -: 2)#?

Answer 1

174

Consider PEMDAS (Parentheses, Exponents, Multiplication, Division, Addition, Subtraction).

Begin by solving what is in parentheses: #[(13)*(4)^2]-(34)# Solve the expression in the last set of parentheses from right to left.

Next, solve for expressions involving exponents: #[13*16]-34#

Now multiply: #208-34#

And subtract: #174#

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Answer 2

Emery Allen

To solve the expression ([(8+5) \times (6-2)^2] - (4 \times 17 \div 2)), follow the order of operations (PEMDAS/BODMAS):

First, calculate the value inside the parentheses: ((8+5) = 13) and ((6-2) = 4).
Next, raise (4) to the power of (2), which equals (16).
Then, multiply (13) by (16), which results in (13 \times 16 = 208).
After that, calculate (4 \times 17), which is (68).
Finally, divide (68) by (2), which equals (34).

Now, subtract (34) from (208) to get the final result:

[ 208 - 34 = 174 ]

Therefore, the value of ([(8+5) \times (6-2)^2] - (4 \times 17 \div 2)) is (174).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

What is #[(8+5)*(6-2) ^2] - (4*17 -: 2)#?

What is #[(8+5)(6-2) ^2] - (417 -: 2)#?