What is #4\cdot 2- 3( 2- 5) + 6\div 2#?

Answer 1

#20#

Always count the number of terms first. Each term will simplify to a single number. Keep them separate until the last line where you will add or subtract to get the final answer.

You can calculate within each term in a line.

Within each term the order of operations applies, do brackets first, then from strongest to weakest:

Powers and Roots, then Multiply and Divide Last: Add and Subtract.

#4xx2 -3(2-5)+6div2" "larr# there are 3 terms
=#color(red)(4xx2)color(blue)( -3(2-5))color(seagreen)(+6div2)" "larr# keep them separate
=#color(red)(8)color(white)(xxx)color(blue)( -3(-3))color(white)(xxx)color(seagreen)(+3)#
=#color(red)(8)color(white)(xxxxxx)color(blue)( +9)color(white)(xxxx)color(seagreen)(+3)" "larr# now add
=#20#
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Answer 2

The answer is #20# remember use PEMDAS

P stands for Parenthesis so Parenthesis must be done first.

#( 2-5) = -3# two is going up -5 is going down so direction is 3 more down than up.
# 4 xx 2 -3 xx -3 + 6/2# is the new problem. There are no exponents so go on to MD

MD stands for Multiplication and Division. Think Medical Doctor=MD

A Medical Doctor is one person not two. MD must be done together, can't cut the doctor in half. So we must work from left to right doing all the multiplication and division before doing any addition or subtraction.

# 4 xx 2 = +8# # -3 xx -3 = +9 # # 6/2 =+ 3#
( a negative times a negative equals a positive.) Think: a negative is something bad. A negative is the sign for subtraction, or to take away. So to take away something bad is good. Good is positive. # (-) xx (-) = +#
#8+ 9 + 3# is the new problem.

Add them from left to right

#8+9 = 17# so the new problem is
#17 + 3 = 20#

Remember if you get hurt in PE call an MD Asap

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Answer 3

The expression simplifies to ( 4 \times 2 - 3 \times (2 - 5) + 6 \div 2 = 8 - 3 \times (-3) + 6 \div 2 = 8 + 9 + 3 = 20 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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