What is #4##3/10##- ##3# #3/5#?

Question

Emery Allen · Accepted Answer

#7/10# #4 3/10# can be written as an improper fraction #color(white)("XXX")(4xx10+3)/10=43/10# #3 3/5# can be written as an improper fraction #color(white)("XXX")(3xx5+3)/5=(18/5)# #18/5# can be written with a denominator of #10# to match the #4 3/10=43/10# term #color(white)("XXX")(18xx2)/(5xx2)=36/10# Therefore #color(white)("XXX")4 3/10 - 3 3/5# is equivalent to #color(white)("XXX")43/10 - 36/10# #color(white)("XXX")=7/10#

Gianna Caruso · Answer

undefined To subtract $ \frac{43}{10} $ from $ \frac{3}{5} $, we first convert both fractions to have a common denominator. The least common denominator for 10 and 5 is 10.

For $ \frac{43}{10} $, we multiply the numerator and denominator by 1 to maintain the value:

$$ \frac{43}{10} = \frac{43 \times 1}{10 \times 1} = \frac{43}{10} $$

For $ \frac{3}{5} $, we multiply the numerator and denominator by 2:

$$ \frac{3}{5} = \frac{3 \times 2}{5 \times 2} = \frac{6}{10} $$

Now that both fractions have a common denominator of 10, we can subtract them:

$$ \frac{43}{10} - \frac{6}{10} $$

Subtracting the numerators:

$$ \frac{43 - 6}{10} = \frac{37}{10} $$

Therefore, $ \frac{43}{10} - \frac{3}{5} = \frac{37}{10} $.