What is #|| <-1, 4, 2 > - < -2 , -7, 3 > ||#?

Answer 1

#sqrt123# units.

The problem asks for the two vectors' subtraction's magnitude.

#(-1,4,2)-(-2,-7,3)=(1,11,-1)#
Magnitude of the resulting vector is #sqrt(1^2+11^2+1^2)=sqrt123#
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Answer 2

The result is 13.

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Answer 3
The expression || <-1, 4, 2> - <-2, -7, 3> || represents the magnitude (or length) of the vector resulting from the subtraction of the second vector from the first vector. To find the result: 1. Subtract the corresponding components of the two vectors. 2. The resulting vector is <-1 - (-2), 4 - (-7), 2 - 3> = <1, 11, -1>. 3. Calculate the magnitude of this resulting vector using the formula: ||v|| = sqrt(v1^2 + v2^2 + v3^2). Plugging in the values, we get ||<1, 11, -1>|| = sqrt(1^2 + 11^2 + (-1)^2) = sqrt(1 + 121 + 1) = sqrt(123) ≈ 11.09. So, || <-1, 4, 2> - <-2, -7, 3> || is approximately 11.09.
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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