What intermolecular forces are present in #CH_3F#?
Dipole-Dipole and London (Dispersion) Forces.
Great question!
If we look at the molecule, there are no metal atoms to form ionic bonds. Furthermore, the molecule lacks hydrogen atoms bonded to nitrogen, oxygen, or fluorine; ruling out hydrogen bonding. Finally, there is a dipole formed by the difference in electronegativity between the carbon and fluorine atoms. This means the fluoromethane molecule will have a strong dipole-dipole force. As all molecules have the London (dispersion) force as caused by the electrons and positive nuclei, it too is present.
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The intermolecular forces present in CH₃F are dipole-dipole forces and London dispersion forces.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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