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What impulse occurs when an average force of 9 N is exerted on a 2.3 kg cart, initially at rest, for 1.2 s? What change in momentum does the cart undergo? What is the cart's final speed?

Answer 1

Isabella Alvarez

#∆p = 11 Ns#
#v = 4.7 m.s^(-1)#

Impulse (∆p) #∆ p = Ft = 9 × 1.2 = 10.8 Ns# Or #11 Ns# (2 s.f.)

Impulse = change in momentum, so change in momentum = #11 kg.m.s^(-1)#

Final velocity m = 2.3 kg, u = 0, v = ?

#∆p = mv - mu = mv - 0 ⇒ v = (∆p)/m = 10.8/2.3 = 4.7 m.s^(-1)#

The direction of the velocity is in the same direction as the force.

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Answer 2

Carson Alexander

Impulse: 10.8 N·s Change in momentum: 10.8 kg·m/s Final speed: 4.7 m/s

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.