What force on a floating object displaces 0.6 m3 of water?
The weight of the liquid or gas that the object has displaced equals the buoyancy force.
reorganize (find m):
*You must convert the V to a cubic meter or cm if it is provided to you in liters.
now replace
now locate the power
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The force on a floating object displacing 0.6 m^3 of water is equal to the weight of the water displaced, which is determined by the buoyant force acting on the object. According to Archimedes' principle, the buoyant force is equal to the weight of the fluid displaced by the object, regardless of the object's density or shape. Therefore, to calculate the force, you would need to multiply the density of water (approximately 1000 kg/m^3) by the volume of water displaced (0.6 m^3), and then multiply by the acceleration due to gravity (approximately 9.8 m/s^2). The formula for calculating the buoyant force is: Buoyant force = density of fluid × volume of fluid displaced × acceleration due to gravity.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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