What does #(x^3-7x-6) / (x+1) # equal?
Simplify Ans:
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The expression (x^3-7x-6) / (x+1) equals x^2 - x - 8.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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- How do you simplify the expression #(x^2-x-12)/(x^2-6x+8)#?
- How do you solve #x/(2x-3) + 4/(x+1) = 1#?
- How do you multiply #3y ^ { 2} + 6y + 5# and #y - 9# using the vertical format?

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