What carboxylic acid and reagents need to prepare (a)N,N,2-trimethylpropanamide (b)Ethyl benzoate and (c)propanoyl chloride ?

Question

What carboxylic acid and reagents need to prepare (a)N,N,2-trimethylpropanamide (b)Ethyl benzoate and (c)propanoyl chloride  ?

Madison Anderson · Accepted Answer

You need (a) 2-methylpropanoic acid, (b) benzoic acid, and (c) propanoic acid.

(a) Preparation of N,N,2-trimethylpropanide Convert 2-methylpropanoic acid to 2-methylpropanoic acid with #"PCl"_5#, then react it with dimethylamine. #("CH"_3)_2"CHCOOH" stackrelcolor(blue)("PCl"_5 color(white)(m))(→) ("CH"_3)_2"CHCOCl" stackrelcolor(blue)("HN"("CH"_3)_2color(white)(m) )(→) ("CH"_3)_2"CHCON"("CH"_3)_2 # (b) Preparation of ethyl benzoate Heat benzoic acid with ethanol and sulfuric acid as catalyst. #"C"_6"H"_5"COOH"stackrelcolor(blue)( "CH"_3"CH"_2"OH"color(white)(m))(→) "C"_6"H"_5"COOCH"_2"CH"_3# #color(white)(mmmmmmm)stackrelcolor(blue)(Δ, "H"_2"SO"_4)(color(white)(m)# (c) Preparation of propanoyl chloride Use #"PCl"_5# to convert propanoic acid to propanoyl chloride. #"CH"_3"CH"_2"COOH" stackrelcolor(blue)("PCl"_5 color(white)(m))(→) "CH"_3"CH"_2"COCl" #

Zoe Alexander · Answer

undefined (a) To prepare N,N,2-trimethylpropanamide, you would start with 2,2-dimethylpropanoic acid as the carboxylic acid. The reagents required would be thionyl chloride (SOCl2) and then dimethylamine (CH3)2NH.

(b) To prepare Ethyl benzoate, you would start with benzoic acid as the carboxylic acid. The reagent needed would be ethanol (C2H5OH), and a strong acid catalyst such as concentrated sulfuric acid (H2SO4) might be used to facilitate the reaction.

(c) To prepare Propanoyl chloride, you would start with propanoic acid as the carboxylic acid. The reagent required would be thionyl chloride (SOCl2).