What are x and y if #10x  2y = 8# and #3y  5x = 8#?
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To solve the system of equations (10x  2y = 8) and (3y  5x = 8), you can use the substitution method. Here's how you do it:

Rearrange the first equation to solve for (x): (10x  2y = 8) becomes (10x = 2y  8), which simplifies to (x = \frac{2y  8}{10}) or (x = \frac{y  4}{5}).

Substitute the expression for (x) from the first equation into the second equation: (3y  5\left(\frac{y  4}{5}\right) = 8).

Simplify the equation and solve for (y): (3y  y + 4 = 8), (2y + 4 = 8), (2y = 4), (y = 2).

Substitute (y = 2) back into the expression for (x) to find (x): (x = \frac{2(2)  8}{10}), (x = \frac{4  8}{10}), (x = \frac{4}{10}), (x = 0.4).
So, the solution to the system of equations is (x = 0.4) and (y = 2).
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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