# What are the x-intercepts of #x²-y+2x=6 #?

The x-intercepts are at

We first isolate y.

Note that we know that(and it will, if you are correct) when we plug in the zeros, we get zero for the equation.

*Here is the idea of how the zeros are the answer. Since the y value is 0, we know that the point must lie on the x coordinate, which means those points are the x intercepts.

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To find the x-intercepts, set y to 0 and solve for x.

x² - y + 2x = 6

x² - 0 + 2x = 6

x² + 2x = 6

x² + 2x - 6 = 0

(x + 3)(x - 2) = 0

x = -3, 2

The x-intercepts are -3 and 2.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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