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What are the vertex, focus, and directrix of the parabola described by #(x − 5)^2 = −4(y + 2)#?

Answer 1

Ethan Adkins

#(5,-2),(5,-3),y=-1#

#"the standard form of a vertically opening parabola is"#

#•color(white)(x)(x-h)^2=4a(y-k)#

#"where "(h,k)" are the coordinates of the vertex and a"# #"is the distance from the vertex to the focus and"# #"directrix"#

#(x-5)^2=-4(y+2)" is in this form"#

#"with vertex "=(5,-2)#

#" and "4a=-4rArra=-1#

#"Focus "=(h,a+k)=(5,-1-2)=(5,-3)#

#"directrix is "y=-a+k=1-2=-1# graph{(x-5)^2=-4(y+2) [-10, 10, -5, 5]}

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Answer 2

Abigail Allen

Vertex: (5, -2) Focus: (5, -1) Directrix: y = -3

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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