What are the seven isomers of C4H10O?

Answer 1

See below.

The formula indicates that there are no rings or double bonds in these isomers.

Alcohols and ethers are required for the isomers.

First, let's draw the alcohols.

Start with four carbons in a row and put an #"OH"# group in every possible position.

This provides us with

1. #"CH"_3"CH"_2"CH"_2"CH"_2"OH"#, butan 1-ol

and

2. #"CH"_3"CH"_2"CH(OH)CH"_3#, butan-2-ol
Now use a 3-carbon chain with a #"CH"_3# on the middle carbon.

This provides

#("CH"_3)_2"CHCH"_2"OH"#, 2-methylpropan-1-ol

additionally

#("CH"_3)_3"COH"#, 2-methylpropan-2-ol.

The ethers are next.

Let's begin with a row of five atoms.

This provides

#"CH"_3"CH"_2"CH"_2"OCH"_3#, 1-methoxypropane

additionally

#"CH"_3"CH"_2"OCH"_2"CH"_3#, ethoxyethane

Lastly, for a branched-chain ether, the only option is

#("CH"_3)_2"CHOCH"_3#, 2-methoxpropane.
And there are your seven isomers of #"C"_4"H"_10"O"#.
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Answer 2

The seven isomers of C4H10O are butanol, 2-methyl-1-propanol, 1-butanol, 2-butanol, 2-methyl-2-propanol, 1-methyl-2-propanol, and tert-butanol.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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