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What are the real zeros for #h(t)=-2t^3+23t^2-59t+24#?

Answer 1

Isaiah Anthony

#(t-8)(t-3)(2t-1)#

Using the rational root Theorem we get

#t_1=8# #t_2=3# and then solve a linear equation.

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Answer 2

Jace Anderson

To find the real zeros of ( h(t) = -2t^3 + 23t^2 - 59t + 24 ), you need to solve the equation ( h(t) = 0 ). This can be done by factoring, using the rational root theorem, or using numerical methods. After solving the equation, you'll get the real zeros of the function.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.