What are the products of the following reaction: #CH_3-C(CH_3)=CH-CH_3 + HBr #? Is it antimarkovnikov?
Antimarkovnikov is the outcome if hydrogen peroxide and HBr are present in the reaction.
Please double-check your question; it's possible that you left out the peroxide.
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The products of the reaction are 2-bromo-2-methylbutane and hydrogen bromide. This reaction follows Markovnikov's rule, not anti-Markovnikov, as the hydrogen atom adds to the carbon atom with more hydrogen atoms attached (secondary carbon), leading to the formation of the more stable carbocation intermediate.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- Does radical halogenation only occur in alkanes?
- Why is the relative stability of radicals different than that of carbocations?
- Of 2-bromo-3-methylbutane , 2-chlorobutane , 2-chloro-2-methylpropane, which haloalkanes will give 3,4-dimethylhexane when treated with sodium metal (Wurtz reaction)? Write the reaction equation?
- 3,4-dimethoxybenzaldehyde is treated with bromine.What will be the product/s ?
- Why are the higher alkanes more toxic?

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