What are the points of inflection, if any, of #f(x)=-3x^3+270x^2-3600x+18000 #?

Answer 1

At #x=30#, there is a point of inflection

Given -

#y=-3x^3+270x^2-3600x+18000#

We must set the send derivative to zero in order to determine the point of inflection.

#dy/dx=9x^2+540x-3600#
#(d^2y)/(dx^2)=18x+540#
Set #(d^2y)/(dx^2)=0#

Then -

#18x+540=0# #x=540/18=30#
At #x=30#, there is a point of inflection
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Answer 2

To find the points of inflection, we first need to find the second derivative of the function and then solve for the values of x where the second derivative equals zero or is undefined.

The first derivative of ( f(x) ) is: ( f'(x) = -9x^2 + 540x - 3600 )

The second derivative of ( f(x) ) is: ( f''(x) = -18x + 540 )

Setting ( f''(x) ) equal to zero and solving for x: ( -18x + 540 = 0 ) ( x = 30 )

So, the point of inflection is ( (30, f(30)) ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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