What are the mean and standard deviation of a binomial probability distribution with #n=5 # and #p=4/7 #?
Mean is
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The mean ((\mu)) of a binomial probability distribution is calculated using the formula:
[ \mu = n \times p ]
where (n) is the number of trials and (p) is the probability of success on each trial.
The standard deviation ((\sigma)) of a binomial probability distribution is calculated using the formula:
[ \sigma = \sqrt{n \times p \times (1 - p)} ]
Substituting (n = 5) and (p = \frac{4}{7}) into the formulas, we can find the mean and standard deviation:
Mean ((\mu)): [ \mu = 5 \times \frac{4}{7} ]
Standard deviation ((\sigma)): [ \sigma = \sqrt{5 \times \frac{4}{7} \times \left(1 - \frac{4}{7}\right)} ]
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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