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What are the intercepts of #-3y+3x=1#?

Answer 1

#x# int #=1/3#
#y# int #=-1/3#

Lets change this into #y=mx+b# form. #-3y+3x=1# take away #3x# from both sides #-3y=1-3x# divide by #-3# from both sides #y=-1/3+x# New equation: #y=-1/3+x#

X intersect For #x# int, put #y=0# #0=-1/3+x# add #1/3# on both sides #1/3=x# #x# int =#1/3#

Y intersect For #y# int, put #x=0# #y=-1/3+0# #y=-1/3# #y# int = #-1/3#

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Answer 2

Eva Abramson

To find the x-intercept, set y to 0 and solve for x.
To find the y-intercept, set x to 0 and solve for y.

For x-intercept:
-3y + 3x = 1
-3(0) + 3x = 1
3x = 1
x = 1 / 3
For y-intercept:
-3y + 3(0) = 1
-3y = 1
y = 1 / -3
y = -1/3

So, the x-intercept is (1/3, 0) and the y-intercept is (0, -1/3).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.