# What are the intercepts of #2x-13y=-17#?

A y-axis intercept occurs on the axis when the x value is equal to 0. The same with the x-axis and the y value being equal to 0

So if we let x=0, we will be able to solve for the y value at the intercept.

So the y-axis intercept occurs when x=0 and y=17/13 giving the co-ordinate.

To find the x-axis intercept we do the same thing but let y=0.

The x-axis intercept occurs when y=0 and x=-17/2 giving the co-cordinate

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To find the intercepts of the equation (2x - 13y = -17), you can set one variable to zero and solve for the other variable.

To find the x-intercept, set (y = 0) and solve for (x):

(2x - 13(0) = -17)

(2x = -17)

(x = -\frac{17}{2})

To find the y-intercept, set (x = 0) and solve for (y):

(2(0) - 13y = -17)

(-13y = -17)

(y = \frac{17}{13})

Therefore, the x-intercept is (-\frac{17}{2}) and the y-intercept is (\frac{17}{13}).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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