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What are the intercepts for #y= - 2/3x - 12#?

Answer 1

Kennedy Adams

x-intercept is: #x=-18#
y-intercept is: #y=-12#

#y= - 2/3x - 12#

This is in the slope point form #y=mx+b#, m is the slope and b is the y-intercept.

#m=-2/3#

#b = -12#

So y-intercept is: #y=-12#

to find the x-intercept set #y=0# and solve for #x#:

#0= - 2/3x - 12#

#12= - 2/3x#

#x=-18#

So x-intercept is: #x=-18#

graph{- 2/3x - 12 [-29.75, 10.25, -15.12, 4.88]}

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Answer 2

Ethan Adkins

To find the intercepts, set ( x = 0 ) to find the y-intercept and set ( y = 0 ) to find the x-intercept.

For y-intercept: ( x = 0 )
( y = -\frac{2}{3}(0) - 12 )
( y = -12 )

For x-intercept: ( y = 0 )
( 0 = -\frac{2}{3}x - 12 )
( \frac{2}{3}x = -12 )
( x = -\frac{3}{2}(12) )
( x = -18 )

Therefore, the y-intercept is ( (0, -12) ) and the x-intercept is ( (-18, 0) ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.