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What are the important points needed to graph #y=x^2+2x+1#?

Answer 1

Graph #f(x) = x^2 + 2x + 1.#

The important points are: 1. x-coordinate of axis of symmetry. x = -(b/2a) = -2/2 = -1. 2. x-coordinate of vertex: x = -(b/2a) = -1 y-coordinate of vertex: f(-1) = 1 - 2 + 1 = 0 3. y intercept. Make x = 0 --> y = 1 4. x-intercepts. Make y = 0 and solve #f(x) = x^2 + 2x + 1 = (x + 1)^2 = 0# There is double root at x = -1. graph{x^2 + 2x + 1 [-10, 10, -5, 5]}

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Answer 2

Avery Alexander

The important points needed to graph ( y = x^2 + 2x + 1 ) are:

The vertex coordinates: ( (-b/2a, f(-b/2a)) ), where ( a = 1 ) and ( b = 2 ).
The y-intercept: (0, 1).
The axis of symmetry: ( x = -b/2a ).
Additional points obtained by choosing values for ( x ) and calculating ( y ) using the equation.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.