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What are the factors of the polynomial #x^2+5x-14#?

Answer 1

#x^2 +5x -14 = (x+7)(x-2)#

Many quadratic trinomials can be factored.

There is no common factor in all the terms.

The numerical coefficient of #x^2# is 1, its factors are # 1 and 1,# which when multiplying, will not change any values.

FInd the factors of 14 which subtract to make 5.

#14 = 1xx14 " "rarr 1-14 = 13" "# not what we want

#14 = 2xx7" "rArr 7-2 = 5" " exactly what we want.

the signs will be different, but there must be more positives to give #+5x# as the middle term.

#x^2 +5x -14 = (x+7)(x-2)#

Multiplying out to check gives:

#x^2 -2x+7x-14 = x^2 +5x-14#

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.