# What are the extrema of #f(x) = 7e^x#?

There are no extrema

Hence there are no extrema!

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The function ( f(x) = 7e^x ) has one critical point at ( x = 0 ). Since the function is continuously increasing, there are no relative extrema. However, the function has an absolute minimum at ( x = 0 ), where ( f(0) = 7 ). Therefore, ( f(x) = 7e^x ) has an absolute minimum of ( 7 ) at ( x = 0 ).

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