What are the equations of the tangents drawn from the point (0,1) to the circle #x^2+y^2-2x+4y=0#?
The equations of tangents are
graph{(x+2y-2)(2x-y+1)(x^2+y^2-2x+4y)(x^2+(y-1)^2-0.01)=0 [-4.69, 5.31, -3.5, 1.5]}
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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- How do you find the center and radius of the circle #x^2 + y^2 - 8y = 9#?
- What is the equation of the circle with endpoints of the diameter of a circle are (7,4) and (-9,6)?
- How do you write the equation of the circle which passes through the point A(-2,0) AND b(5,1)?

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