# What are the critical values, if any, of #f(x)= 5x^2 +4x#?

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To find the critical values of the function ( f(x) = 5x^2 + 4x ), we first need to find its derivative, set it equal to zero, and solve for ( x ).

( f'(x) = 10x + 4 )

Setting the derivative equal to zero:

( 10x + 4 = 0 )

Solving for ( x ):

( 10x = -4 )

( x = -\frac{4}{10} )

( x = -\frac{2}{5} )

Therefore, the critical value of the function is ( x = -\frac{2}{5} ).

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