# What are the asymptote(s) and hole(s), if any, of # f(x) =(x^2-1)/(x^4-1) #?

Double asymptote

So

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The function f(x) = (x^2-1)/(x^4-1) has two vertical asymptotes at x = 1 and x = -1. There are no horizontal asymptotes. The function has a hole at x = -1.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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- How do you graph #f(x)= (x^3+1)/(x^2-4)#?

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