What are four consecutive even integers whose sum is 340?

Answer 1
Suppose the even numbers are #n#, #n+2#, #n+4# and #n+6#.

Then

#340 = n + (n+2) + (n+4) + (n+6) = 4n+12#
Subtract #12# from both ends to get
#4n = 328#
Divide both ends by #4# to get
#n = 82#
So the four numbers are: #82#, #84#, #86# and #88#.
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Answer 2

Let ( x ) be the first even integer. Then the consecutive even integers are ( x, x+2, x+4, ) and ( x+6 ). The sum of these integers is ( x + (x+2) + (x+4) + (x+6) = 4x + 12 ). Setting this equal to 340 and solving for ( x ) gives ( x = 82 ). Therefore, the consecutive even integers are 82, 84, 86, and 88.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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