Vance wants to have pictures framed. Each frame and mat costs $32 and he has at most $150 to spend. How do you write and solve an inequality to determine the number of pictures he can have framed?

Answer 1

Number of pictures can be framed is #4#

Let number of pictures can be framed is #x#
Cost of framing is #$32# for one picture.
#:. x*32 <=150 or x <= 150/32 or x <= 4.6875#

Number of pictures must be an integer.

#:. x =4 #
Hence number of pictures can be framed is #4# [Ans]
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Answer 2

Let ( x ) represent the number of pictures Vance wants to have framed. The total cost of framing ( x ) pictures is ( 32x ). Since Vance has at most $150 to spend, the inequality representing this situation is: [ 32x \leq 150 ] To solve for ( x ), divide both sides of the inequality by 32: [ x \leq \frac{150}{32} ] [ x \leq 4.6875 ] Since Vance cannot have a fraction of a picture framed, the maximum number of pictures he can have framed is 4.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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