Under what reaction conditions does the electrophilic bromination of aromatic compounds usually occur?
Bromination of an aromatic compound by electrophilic substitution requires a Lewis acid catalyst to polarise a bromine to bromine bond,
A pair of electrons from the six delocalized pi electron system forms a bond by donating them to the electron deficient bromine atom, which breaks down the benzene rings aromacity and therefore leads to the ejection of the proton to reform the aromacity of the benzene ring. The proton bonds with the bromide ion to form HBr, the product being bromobenzene. A bromine molecule requires a Lewis acid catalyst, such as Iron (III) bromide, to polarise the halogen bond, so one bromine atom is electron deficient and the bromine near the Lewis acid is electron rich.
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The electrophilic bromination of aromatic compounds usually occurs under acidic reaction conditions.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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