Two sources produce electromagnetic waves. Source A produces a wavelength that is three times the wavelength produced by source B. Each photon from source B has an energy of 2.1*10^-18 J. What is the energy of a photon from source A?

Answer 1

I found #7xx10^-19J#

We can use Einstein's formula for the energy of a photon: #E=h*nu# Where: #h=6.63xx10^-34Js# is Planck's constant: #nu=#frequency. Also we remember the relationship between wavelngth #lambda# and frequenct #nu# through the speed of light in vacuum #c=3xx10^8m/s# as: #c=lambda*nu#
So the energy from source A will be: #E_A=h*nu_A=hc/lambda_A# and for source B: #E_B=2,1xx10^-18=h*nu_B=hc/lambda_B# so: #lambda_B=(hc)/(2.1xx10^-18)#
BUT: #lambda_A=3lambda_B# so: #E_A=h*nu_A=hc/lambda_A=(hc)/(3lambda_B)=(hc)/3*(2.1xx10^-18)/(hc)=(2.1xx10^-18)/3=7xx10^-19J#
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Answer 2

(6.3 \times 10^{-18} , \text{J})

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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