# Two satellites are in circular orbits around the earth. The orbit for satellite A is at a height of 539 km above the earth's surface, while that for satellite B is at a height of 876 km. How do you find the orbital speed for satellite A and satellite B?

Regarding satellite A:

Regarding satellite B:

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The orbital speed of a satellite in a circular orbit around the Earth can be calculated using the formula:

[ v = \sqrt{\frac{GM}{r}} ]

Where:

- ( v ) is the orbital speed (in meters per second).
- ( G ) is the gravitational constant (( 6.674 \times 10^{-11} ) m³/kg/s²).
- ( M ) is the mass of the Earth (( 5.972 \times 10^{24} ) kg).
- ( r ) is the radius of the orbit (Earth's radius plus the height of the orbit).

For satellite A: [ r_A = 539 \text{ km} + 6371 \text{ km} = 6910 \text{ km} ]

For satellite B: [ r_B = 876 \text{ km} + 6371 \text{ km} = 7247 \text{ km} ]

Now, using the formula:

[ v_A = \sqrt{\frac{6.674 \times 10^{-11} \times 5.972 \times 10^{24}}{6910000}} ]

[ v_B = \sqrt{\frac{6.674 \times 10^{-11} \times 5.972 \times 10^{24}}{7247000}} ]

Calcula

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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