# Two rhombuses have sides with lengths of #8 #. If one rhombus has a corner with an angle of #pi/12 # and the other has a corner with an angle of #(5pi)/8 #, what is the difference between the areas of the rhombuses?

Area of rhombus

Where

In this case we will use the formula Area = a * h.

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To find the area of a rhombus, you can use the formula: Area = (diagonal1 * diagonal2) / 2.

Given that both rhombuses have sides of length 8, we can calculate their diagonals. The diagonals of a rhombus are perpendicular bisectors of each other.

For the rhombus with an angle of π/12, the diagonals will have lengths of 8 and 8 * tan(π/12).

For the rhombus with an angle of (5π)/8, the diagonals will have lengths of 8 and 8 * tan((5π)/8).

Once you find the lengths of the diagonals for both rhombuses, plug them into the area formula and find the difference in their areas.

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The difference between the areas of the rhombuses is ( 32 - 32\sqrt{2} ) square units.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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