Two rhombuses have sides with lengths of #6 #. If one rhombus has a corner with an angle of #pi/12 # and the other has a corner with an angle of #(5pi)/12 #, what is the difference between the areas of the rhombuses?

Answer 1

#=25.46#

Area of the rhombus with angle #theta=(pi)/12# and Side #a=6# is #=a^2 sin theta# #=6^2 sin((pi)/12)# #=36(0.2588)# #=9.32# Area of the rhombus with angle #theta=(5pi)/12# and Side #a=6# is #=a^2 sin theta# #=6^2 sin((5pi)/12)# #=36(0.966)# #=34.78# So difference in Area#=34.78-9.32=25.46#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Allison Allen

The difference between the areas of the two rhombuses is 18 square units.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.