# Two rhombuses have sides with lengths of #2 #. If one rhombus has a corner with an angle of #pi/3 # and the other has a corner with an angle of #(5pi)/8 #, what is the difference between the areas of the rhombuses?

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To find the area of a rhombus, you can use the formula: Area = (diagonal1 * diagonal2) / 2. Given that the side length of both rhombuses is 2, the diagonals of each rhombus can be calculated using trigonometry. For the rhombus with an angle of π/3, the diagonals are 2 and 2/sin(π/3). For the rhombus with an angle of (5π)/8, the diagonals are 2 and 2/sin((π/2) - (5π/8)). Once you have the diagonals for both rhombuses, plug them into the area formula and find the difference.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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- A parallelogram has sides A, B, C, and D. Sides A and B have a length of #2 # and sides C and D have a length of # 1 #. If the angle between sides A and C is #(7 pi)/18 #, what is the area of the parallelogram?
- Two rhombuses have sides with lengths of #9 #. If one rhombus has a corner with an angle of #pi/12 # and the other has a corner with an angle of #(7pi)/8 #, what is the difference between the areas of the rhombuses?

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