Two rhombuses have sides with lengths of #2 #. If one rhombus has a corner with an angle of #pi/12 # and the other has a corner with an angle of #pi/2 #, what is the difference between the areas of the rhombuses?

Answer 1
The area of a rhombus #A=a^2xxsintheta#, where a is the length of the side of the rhombus and #theta# is the angle between them
The Rhombus having angle #theta = pi/2 # will have area #A_1=2^2xxsin(pi/2)=4#squnit The are of other rhombus =#A_2=2^2xxsin(pi/12)=1#squnit So difference =#4-1=3squnit#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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