# Two rhombuses have sides with lengths of #12 #. If one rhombus has a corner with an angle of #pi/3 # and the other has a corner with an angle of #(5pi)/8 #, what is the difference between the areas of the rhombuses?

≈ 8.33 square units

A rhombus has 4 equal sides and is constructed from 2 congruent isosceles triangles.

now the area of 2 congruent triangles ( area of rhombus ) is

difference in area = 133.04 - 124.71 = 8.33 square units

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To find the areas of the rhombuses, you can use the formula: Area = (side length)^2 * sin(angle).

For the first rhombus with an angle of π/3, its area is (12)^2 * sin(π/3) = 72√3 square units.

For the second rhombus with an angle of (5π)/8, its area is (12)^2 * sin((5π)/8) ≈ 120.95 square units.

The difference between the areas of the two rhombuses is approximately 48.95 square units.

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The difference between the areas of the two rhombuses is (12^2 \times \left(\frac{\pi}{3} - \frac{5\pi}{8}\right)).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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