Two rectangles are similar. the dimension of the first are 2 feet x 8 feet. if the lenght of the second is 20 feet, what is its width?

Answer 1

#5# ft

We know that similar rectangles are the rectangles those are of same shape but have dissimilar sizes.

Two rectangles are similar if the measurement of their corresponding sides are in the same ratio. Therefore, we have the expression

#"Length of one rectangle"/"Width of same rectangle"="Length of other rectangle"/"Width of other rectangle"#

Inserting given values in above we get

#8/2=20/"Width of other rectangle"# or #"Width of other rectangle"=20xx2/8=cancel40^5/cancel8^1=5'#

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Answer 2

Allison Allen

If two rectangles are similar, their corresponding sides are proportional. Therefore, if the length of the second rectangle is 20 feet and the length of the first rectangle is 8 feet, the ratio of corresponding lengths is ( \frac{20}{8} = \frac{5}{2} ). Since the dimensions of the first rectangle are given as 2 feet by 8 feet, the width of the second rectangle can be found by multiplying the width of the first rectangle by the same ratio. Thus, the width of the second rectangle is ( 2 \times \frac{5}{2} = 5 ) feet.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.