Two opposite sides of a parallelogram have lengths of #12 #. If one corner of the parallelogram has an angle of #pi/4 # and the parallelogram's area is #42 #, how long are the other two sides?

Answer 1

#=4.95#

Area of the Parallelogram = #a#x #b# x #sintheta# where a and b are sides and θ is the angle between them. So we got #a=12# and #theta = pi/4#or #45^@# We have to find out b= ?

So we write Area =#42#=#ab sintheta# or #42=12b sin45# or #b sin45=42/12# or #b sin45=7/2# or #b/sqrt2=7/2# since #sin45=1/sqrt2# or #b=7/sqrt2# or #b=4.95#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Sadie Allen

The other two sides of the parallelogram are of length 7 each.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.