Two opposite sides of a parallelogram each have a length of #35 #. If one corner of the parallelogram has an angle of #(5 pi)/12 # and the parallelogram's area is #210 #, how long are the other two sides?

Answer 1

The other two sides are of #6.21(2dp)# length each.

Let ABCD be the parallelogram of which opposite sides #AB = CD = 35# and corner angle #/_A=5*180/12=75^0# Area of the parallelogram #=AB*h :. 210 = 35*h or h=210/35=6#(h is the altitude i.e DE on AB) Now in the right angled triangle DAE #sin 75=6/(AD) or AD=6/sin75=6.21=BC#[Ans]
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Answer 2

Given that two opposite sides of the parallelogram have a length of 35 and one corner of the parallelogram has an angle of ( \frac{5\pi}{12} ), and the area of the parallelogram is 210, the lengths of the other two sides can be calculated using the formula for the area of a parallelogram and trigonometric ratios.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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