Two opposite sides of a parallelogram each have a length of #15 #. If one corner of the parallelogram has an angle of #(5 pi)/12 # and the parallelogram's area is #160 #, how long are the other two sides?

Answer 1

#b=11#

Area of the parallelogram is #=ab sin theta# where #a=15# is the side and #theta=(5pi)/12# and we have to find #b=?# Therefore Area#=160=15b sin((5pi)/12)# or #bsin((5pi)/12)=160/15# or #b(0.966)=32/3# or #b=11#

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Answer 2

Theodore Abad

The lengths of the other two sides of the parallelogram are 16.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.