Two corresponding sides of two similar triangles are 6cm and 14cm. If the perimeter of the first triangle is 21cm, how do you find the perimeter of the second triangle?

Answer 1

The perimeter of the second triangle is 49cm

because the two triangles are similar their corresponding lengths will be in the same ratio So Side 1 divided by side 2 = perimeter 1 divided by perimeter 2 and thus if the unknown perimeter is x then #6/14# =#21/x# and #6x# = #21xx14# #x# = #(21 xx 14)/6# = 49 So the perimeter of the second triangle is 49cm
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Answer 2

If two triangles are similar, their corresponding sides are in proportion. To find the perimeter of the second triangle, you can set up a proportion using the ratios of corresponding sides between the two triangles.

Let the perimeter of the second triangle be (P_2).

[\frac{6}{14} = \frac{21}{P_2}]

Solve for (P_2).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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