Home > Geometry > Perimeter and Area of Triangle

Two corners of an isosceles triangle are at #(5 ,2 )# and #(2 ,1 )#. If the triangle's area is #7 #, what are the lengths of the triangle's sides?

Answer 1

Lengths of three sides of triangle are #3.16, 4.70,4.70# unit

The base of the isosceles triangle, #b=sqrt( (x_1-x_2)^2+(y_1-y_2)^2) = sqrt( (5-2)^2+(2-1)^2) =sqrt10=3.16(2dp)unit #

The area of the isosceles triangle is #A_t = 1/2 * b *h =1/2*3.16 *h ; A_t=7 :. h = (2* A_t )/b = (2*7)/3.16=14/3.16= 4.43(2dp) unit#. Where #h# is the altitude of triangle.

The legs of the isosceles triangle are #l_1=l_2= sqrt(h^2+(b/2)^2)=sqrt(4.43^2+(3.16/2)^2) =4.70(2dp) unit#

Hence the length of three sides of triangle are #3.16(2dp), 4.70(2dp) ,4.70(2dp)# unit [Ans]

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Savannah Aguilar

To find the lengths of the sides of the isosceles triangle, first, calculate the distance between the given points using the distance formula. Then, use the formula for the area of a triangle to determine the height. Finally, use the formula for the area of a triangle (area = 0.5 * base * height) to find the lengths of the sides.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.