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Two consecutive odd integers have a sum of 128, what are the integers?

Answer 1

#63 " and " 65#

My strategy for doing problems like this is to divide #128# in half, and take the odd integer directly above and below the result. Doing this for #128# yields this:

#128/2=64#

#64-1=63# #64+1=65#

#63+65=128#

As #63# and #65# are two consecutive odd integers that sum to #128#, this satisfies the problem.

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Answer 2

Ethan Adkins

they are #63# and #65#.

since the two numbers are odd, and consecutive, they have a difference of #2#. suppose the smaller integer of the two #= x# #128=x+(x+2)# #=2x+2#

so as to find the smaller odd integer, you need to find the value of #x#: #128-2=2x+2-2# #=126=2x#

#126/2=(2x)/2=63#

#x=63#

63 is the smaller number, so the bigger number is #63+2=65#

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.