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Two consecutive integers have a sum of 113. How do you find the integers?

Answer 1

Julia Adams

The two numbers are #56# and #57#.

Let the two consecutive integers be #x# and #(x+1)#. Therefore:

#x+(x+1)=113#

Open the brackets and simplify.

#x+x+1=113#

#2x+1=113#

Subtract #1# from both sides and then divide both sides by #2#.

#2x=112#

#x=56#

#:. (x+1)=57#

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Answer 2

Kennedy Adams

The consecutive integers are 56 and 57.

#56+57 = 113#

Define the two integers with variables first.

Consecutive numbers are those which follow each other in sequence. 12, 13, 14, 15 ....

They always differ by 1,

If we let the first integer be #x#, then the second is #x+1#

The sum is 113, so write an equation to show this..

#x + x+1 = 113#

#2x = 113-1" "larr# subtract 1 from both sides

#2x = 112#

#x = 56#

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Answer 3

Kennedy Adams

Let ( x ) represent the smaller integer. Then, the next consecutive integer can be represented as ( x + 1 ). Given that their sum is 113, we can set up the equation ( x + (x + 1) = 113 ). Simplifying this equation yields ( 2x + 1 = 113 ). Solving for ( x ) gives ( x = 56 ). Therefore, the two consecutive integers are 56 and 57.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.